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08292016, 01:19 AM #1Senior Member
Is f16 the same on different lenses?
My question is:
Is f16 the same on a f2.8 lens or a f5.6 lens at the same focal length?
I would think that the larger elements of a f2.8 lens would allow more light through than a lens with smaller elements.
Maybe a dumb question but, consider the source!
Thanks
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 08292016, 01:19 AM

08292016, 01:37 AM #2
Re: Is f16 the same on different lenses?
The aperture is measured as a function of the focal length of the lens, and is not at all relative to the maximum aperture of the lens.
So, yes, f/16 would be the same on either one. If it were not, it would be much more difficult, if not impossible, to achieve consistent exposure with different lenses.
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08292016, 01:48 AM #3
Re: Is f16 the same on different lenses?
F/16 is f/16 on every photo lens, whether it's a compact mirrorless or a 20x24 large format.
Many of us will readily recognize the following sequence of numbers:
1, 2, 4, 8, 16, 32, 64, 128, 256, 512.
Save for the first digit (1), each number is twice that of the number to it's left. So you could say that, as you read from left to right, the numbers gets doubled. Conversely, if you were to read the numbers right to left, the numbers get halved.
If you've been involved with photography for a significant length of time, you will also recognize some familiar numbers;.. and you usually call them fstops, or fnumbers.
But those numbers, when stamped into a lens barrel, have some additional numbers in them.
2, 2.8, 4, 5.6, 8, 11, 16, 22, and maybe 32.
And for some reason, you've been told that this sequence, just like the list above, is either doubling or halving depending on which direction you are reading them.
OK, so what gives?
I'll start out with a word of warning;.. if math gives you a headache, you may want to stop here and go do something else. What I'm going to attempt to do is explain Fstops in a bit more detail. And that involves math. No, not rocketscience math or quantum physics. But math nonetheless.
Starting with this: 8 x 2 = 11.
OK, I cheated. f8 x 2 = f11.
Make sense now? I didn't think so. Nor does f8 / 2 = f5.6, right?
To understand those fnumbers, lets take a look at an ordinary camera lens. In this case, I'll use my 105mm Nikkor Micro, which is pictured above. If you want to increase the exposure by one 'stop', you've probably been told to use a smaller number. I'll use going from f8 to f5.6 for this example. F5.6 lets twice as much light in as f8. But even your kids and grandkids know that 8 / 2 = 4, not 5.6!
The reason behind the odd photographic sequence is because fnumbers are actually the result of a ratio. Remember the term quotient from your school days? That's the name given to the results of a simple division problem. Fnumbers are really quotients!
OK, so where do the other two numbers come from (recall dividend or numerator and divisor or denominator? If so, you've probably got a headache now!)? The first number (dividend) is the focal length of your lens. The second number (divisor) is the diameter of the aperture inside your lens.
So let's say you have a 200mm lens. You turn the aperture ring until the aperture blades create a circle inside the lens that measures 25mm in diameter. The result is the equation 200 / 25 = 8. You now have the lens set to f8. If you were to open the aperture until it measures 50mm in diameter, you have the equation 200 / 50 = 4... meaning the lens is set to f4.
In essence, you are letting in four times as much light at f4 as you were with the lens set to f8. F5.6 would be twice as much light as f8.
So now you're probably wondering why f5.6 lets in twice as much light as f8. Why isn't it f4 instead? Well, sorry to say, it's time for some more math; and it's for the same reason 50mm is four times as large as 25mm. Confused? Don't feel bad. It's a concept that takes some people time to wrap their heads around.
Let's take that 25mm opening. How do you calculate the area of that opening? Time to think back to school.. remember the formula? I'll use the value of 3.14 for pi, r is for radius, which is half the diameter. So a 25mm circle will have an area of 3.14 x 12.5 x 12.5 = 3.14 x 156.25 = 490.625 sq. mm.
A 50mm opening would be 3.14 x 25 x 25 = 3.14 x 625 = 1962.5 sq. mm. A 50mm opening, while being twice the diameter as a 25mm opening, has 4 times the area! (1962.5 / 490.625 = 4) So a 50mm opening will let in 4 times as much light!
In order to get twice as much light, you would need a 35.35mm diameter opening (3.14 x 17.68 x 17.68 = 3.14 x 981.51 sq. mm; and 490.625 x 2 is roughly 981.51..remember I'm using roundedoff numbers for simplicity!). And where would this size opening fall into the fstop number? 200 / 35.35 = 5.6.
Does 5.6 sound familiar?
This is why f5.6 lets in twice as much light as f/8.. the area is twice the size not the number (quotient!) itself!
OK, so why not just use the areas created by the aperture blades instead of this seemingly longwinded way? Well, if you told someone you took a shot at ISO 100, 1/640 of a second, and an aperture set to 25 sq. mm.. you may be providing accurate information, but you're not providing complete information.
To explain why, I placed two lenses up on a table and set them both to f8. On the left is a 105mm, on the right is a 28mm. Remember, they're both set to f8! Notice how much larger the opening is on the 105mm on the left compared to the 28mm on the right?
If I set the 105mm lens' aperture to, let's say 10mm diameter, I would have an fnumber of roughly f10.5. But if I set the 28mm to the same 10mm diameter, it would be set to f2.8! To get f10.5 on a 28mm lens, the aperture would need a diameter of 2.67 mm.
So even though the areas created by the aperture blades in lenses of different focal lengths are different; optically they create the same fnumber. And ultimately the same exposure! That's why fnumbers are used instead of the areas created by the aperture blades.. it makes it just that much easier for us to work with. Otherwise, converting aperture areas from one lens to create an identical exposure in another lens would REALLY give you a headache!
So what the manufacturers do when they put seemingly archaic numbers like 2.8, 5.6 and 11 on the lenses is really just taking the math out of the equation for us! So f8 on one lens gives us the same exposure aperture on any other lens! Whether it's a $50 pointandshoot, a vintage 8x10 view camera or a 5digit Hassy dream setup.... f8 is f8.Last edited by 480sparky; 08292016 at 02:09 AM.
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08292016, 03:25 AM #4Senior Member
Re: Is f16 the same on different lenses?
Some lens of the same f stop and focal length will have different t stops. In reality there will likely be differences at the same f stops because lens with same f value often have different t values. I would think it would be very close though.

08292016, 02:27 PM #5
Re: Is f16 the same on different lenses?
@480sparky really liked that post, off to take two headache tablets now.
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08292016, 03:19 PM #6
Re: Is f16 the same on different lenses?
A simpler explanation than Sparky's is that the f/stops are ratios to the length of each lens. I'll use f/4 since the math is easier than f/16, but the principle is the same.
f/4 means that the diameter of the aperture of any lens is 1/4 the size of the lens. So if you have a 200mm lens, divide 200 by 4, and you wind up with 50mm. That means the diameter of the aperture on a 200mm lens when set at f/4 is 50mm.
Compare that with a 50mm lens with an aperture of f/4. Take 50 and divide by 4. The diameter of the aperture on a 50mm lens when set at f/4 is 12.5mm.
The smaller the diameter of the aperture, the more DOF you will have. So f/4 on a 50mm lens will allow greater DOF than f/4 on a 200mm lens. That's where the difference comes in when comparing f/stops. Your DOF will change when comparing different focal lengths.Last edited by hark; 08292016 at 03:21 PM.
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08292016, 03:19 PM
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