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Macro on DX or FX
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<blockquote data-quote="WayneF" data-source="post: 149607" data-attributes="member: 12496"><p>You are right, but there are three ways to look at it.</p><p></p><p>1. With a regular lens in a regular scene (with the subject several or many feet distant), trying two lens on same body, <strong>from standing in the same location </strong>- the longer lens has a telephoto effect, a magnification that is proportional to the focal length (the 100 mm lens image will appear twice as close and large as a 50 mm lens). The shorter lens is wide angle, in comparison.</p><p></p><p>2. With the same one lens on two FX and DX cameras,<strong> from standing in the same location </strong>(several feet), the FX sensor is larger, and so larger simply will show a wider view, more width - from the same lens. The FX and DX image subjects are shown same size (same lens), however when both images are enlarged to the same print size, the FX subject objects will appear smaller. The FX image was NOT smaller (it was the same lens), but the smaller DX frame and view simply must be enlarged more, simulating a telephoto effect, looks closer and larger. See <a href="http://www.scantips.com/lights/cropfactor.html" target="_blank">FX - DX Lens Crop Factor</a></p><p></p><p>3. With Macro at extreme close up, say for 1:1 (in either of two lenses, or in FX and DX bodies), then 1:1 is still 1:1.<strong> 1:1 is NOT about the frame size, but the 1:1 image size is the same size as the actual subject.</strong> But to achieve the same view (width), the DX camera has to stand back more because it is effectively 1.5x longer focal length (if same lens, but simply because of the greater enlargement of its smaller sensor to get the same image) Or - to achieve 1:1, either body will have stand at about 6 inches distance with 105mm lens, instead of maybe 2 inches with 60mm macro lens (working distance, in front of lens). Both are a 1:1 size image (but FX will show a wider view). So with macro, you do not stand in the same place to compare.</p></blockquote><p></p>
[QUOTE="WayneF, post: 149607, member: 12496"] You are right, but there are three ways to look at it. 1. With a regular lens in a regular scene (with the subject several or many feet distant), trying two lens on same body, [B]from standing in the same location [/B]- the longer lens has a telephoto effect, a magnification that is proportional to the focal length (the 100 mm lens image will appear twice as close and large as a 50 mm lens). The shorter lens is wide angle, in comparison. 2. With the same one lens on two FX and DX cameras,[B] from standing in the same location [/B](several feet), the FX sensor is larger, and so larger simply will show a wider view, more width - from the same lens. The FX and DX image subjects are shown same size (same lens), however when both images are enlarged to the same print size, the FX subject objects will appear smaller. The FX image was NOT smaller (it was the same lens), but the smaller DX frame and view simply must be enlarged more, simulating a telephoto effect, looks closer and larger. See [URL="http://www.scantips.com/lights/cropfactor.html"]FX - DX Lens Crop Factor[/URL] 3. With Macro at extreme close up, say for 1:1 (in either of two lenses, or in FX and DX bodies), then 1:1 is still 1:1.[B] 1:1 is NOT about the frame size, but the 1:1 image size is the same size as the actual subject.[/B] But to achieve the same view (width), the DX camera has to stand back more because it is effectively 1.5x longer focal length (if same lens, but simply because of the greater enlargement of its smaller sensor to get the same image) Or - to achieve 1:1, either body will have stand at about 6 inches distance with 105mm lens, instead of maybe 2 inches with 60mm macro lens (working distance, in front of lens). Both are a 1:1 size image (but FX will show a wider view). So with macro, you do not stand in the same place to compare. [/QUOTE]
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