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Great Article On Understanding "Noise"
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<blockquote data-quote="Spottydumplings" data-source="post: 556860" data-attributes="member: 39844"><p>Believe me you are not the only one :confusion:; I don't think that I made it all of the way through the second part!</p><p></p><p>I did, however, follow the link to the article on "Equivalence" and that is where I really started to get confused. In some places it seems to be at odds with things being said in this article; in this one <strong>shot</strong> noise is said to be apparent when the "signal to noise" ratio is low, which I read to mean low <strong>intensity </strong>light where in the Equivalence article <strong>Total Light</strong> crops up (so to speak). I quote:</p><p></p><p>"<em>And this means that, for the same shutter speed, F-number and ISO, the camera with the largest sensor will have more total light to measure. And, unless the large sensor is significantly worse than the smaller one, it will produce a cleaner, less noisy image.</em>"</p><p></p><p>My question here is WHY? Surely you could reverse that logic and say that the larger sensor requires more total light to produce the same exposure? You may have more total light but that does not mean that it is going to be any more intense or better quality; just spread wider.</p></blockquote><p></p>
[QUOTE="Spottydumplings, post: 556860, member: 39844"] Believe me you are not the only one :confusion:; I don't think that I made it all of the way through the second part! I did, however, follow the link to the article on "Equivalence" and that is where I really started to get confused. In some places it seems to be at odds with things being said in this article; in this one [B]shot[/B] noise is said to be apparent when the "signal to noise" ratio is low, which I read to mean low [B]intensity [/B]light where in the Equivalence article [B]Total Light[/B] crops up (so to speak). I quote: "[I]And this means that, for the same shutter speed, F-number and ISO, the camera with the largest sensor will have more total light to measure. And, unless the large sensor is significantly worse than the smaller one, it will produce a cleaner, less noisy image.[/I]" My question here is WHY? Surely you could reverse that logic and say that the larger sensor requires more total light to produce the same exposure? You may have more total light but that does not mean that it is going to be any more intense or better quality; just spread wider. [/QUOTE]
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