Forums
New posts
Search forums
What's new
New posts
New media
New media comments
New profile posts
Latest activity
Media
New media
New comments
Search media
Members
Current visitors
New profile posts
Search profile posts
Log in
Register
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Lenses
Prime
50mm f/1.8 AF-S versus 50mm f/1.8 "D"
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="480sparky" data-source="post: 248160" data-attributes="member: 15805"><p>Let me try this angle:</p><p></p><p>The actual, physical size of the FX and DX sensors are different:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/1Sensorsizecomparison.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p>This is readily apparent if you look at an FX body next to a DX body, and can see the actual sensors when both are set to "Mirror Up for Cleaning":</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/2FXvDXSensorsPost.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p>So how does this translate into anything meaningful out in the 'real world'? Well, lets' pretend we're out there taking photos. And we come across this peaceful scene:</p><p></p><p></p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/3Scene.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p>Now, an FX lens on an FX body has to project a large enough image to cover the larger FX sensor, so it will project an image into the camera that looks like this:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/4FXprojection.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p>(Yeah, I know.... it's right-side-up. In reality, the image would be upside-down, but let's ignore that for the purpose here.)</p><p></p><p>The lens needs to create a large enough image to cover a sensor measuring 24x36mm (represented by the white rectangle):</p><p></p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/5FXSensor.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p>So an FX lens/body will record the final image as:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/6FXFinalImage.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p></p><p></p><p>Now let's take the same focal length lens, but only it's a DX-format lens. It will project a smaller circle:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/7DXProjection.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p></p><p>Because it only needs to cover a sensor that measures 18x24mm:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/8DXSensor.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p>So the same focal length lens, on a DX body, will record a final image as this:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/9DXFinalImage.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p></p><p>Now, if we put the two final images (FX and DX) side by side, we end up with this:</p><p> </p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/10Finalimagecomparison.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p></p><p></p><p>Notice how the subjects in both images are exactly the same size? It's just that the DX sensor recorded a smaller portion of the scene because the sensor is physically smaller! This results in a narrower field of view.</p><p></p><p>So if you compare the sensor size:</p><p></p><p></p><p><img src="http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/1Sensorsizecomparison.jpg" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p></p><p>with the above two images, you should be able to understand the 'crop sensor' effect on field of view.</p></blockquote><p></p>
[QUOTE="480sparky, post: 248160, member: 15805"] Let me try this angle: The actual, physical size of the FX and DX sensors are different: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/1Sensorsizecomparison.jpg [/IMG] This is readily apparent if you look at an FX body next to a DX body, and can see the actual sensors when both are set to "Mirror Up for Cleaning": [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/2FXvDXSensorsPost.jpg [/IMG] So how does this translate into anything meaningful out in the 'real world'? Well, lets' pretend we're out there taking photos. And we come across this peaceful scene: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/3Scene.jpg [/IMG] Now, an FX lens on an FX body has to project a large enough image to cover the larger FX sensor, so it will project an image into the camera that looks like this: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/4FXprojection.jpg [/IMG] (Yeah, I know.... it's right-side-up. In reality, the image would be upside-down, but let's ignore that for the purpose here.) The lens needs to create a large enough image to cover a sensor measuring 24x36mm (represented by the white rectangle): [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/5FXSensor.jpg [/IMG] So an FX lens/body will record the final image as: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/6FXFinalImage.jpg [/IMG] Now let's take the same focal length lens, but only it's a DX-format lens. It will project a smaller circle: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/7DXProjection.jpg [/IMG] Because it only needs to cover a sensor that measures 18x24mm: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/8DXSensor.jpg [/IMG] So the same focal length lens, on a DX body, will record a final image as this: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/9DXFinalImage.jpg [/IMG] Now, if we put the two final images (FX and DX) side by side, we end up with this: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/10Finalimagecomparison.jpg [/IMG] Notice how the subjects in both images are exactly the same size? It's just that the DX sensor recorded a smaller portion of the scene because the sensor is physically smaller! This results in a narrower field of view. So if you compare the sensor size: [IMG]http://i214.photobucket.com/albums/cc172/480sparky/Photography%202/FX%20v%20DX%20FOV%20tutorial/1Sensorsizecomparison.jpg [/IMG] with the above two images, you should be able to understand the 'crop sensor' effect on field of view. [/QUOTE]
Verification
Post reply
Forums
Lenses
Prime
50mm f/1.8 AF-S versus 50mm f/1.8 "D"
Top